abs(3x+2x^2+1)=3

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Solution for abs(3x+2x^2+1)=3 equation: 


Simplifying
abs(3x + 2x2 + 1) = 3

Reorder the terms:
abs(1 + 3x + 2x2) = 3
(1 * abs + 3x * abs + 2x2 * abs) = 3
(1abs + 3absx + 2absx2) = 3

Solving
1abs + 3absx + 2absx2 = 3

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-3 + 1abs + 3absx + 2absx2 = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 1abs + 3absx + 2absx2 = 0

The solution to this equation could not be determined.

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